Ứng dụng…
Và đây là 2 ứng dụng khá đẹp
1)(Nguyễn Huỳnh Khôi Nguyên).Cho a,b,c>0 thỏa ab+bc+ca+abc=4.Chứng minh bdt
![\sqrt[4]{a^2+15}+\sqrt[4]{b^2+15} +\sqrt[4]{c^2+15} \geq \sqrt[4]{1242+54\sqrt[3]{(abc)^2}}](https://s0.wp.com/latex.php?latex=%5Csqrt%5B4%5D%7Ba%5E2%2B15%7D%2B%5Csqrt%5B4%5D%7Bb%5E2%2B15%7D+%2B%5Csqrt%5B4%5D%7Bc%5E2%2B15%7D+%5Cgeq+%5Csqrt%5B4%5D%7B1242%2B54%5Csqrt%5B3%5D%7B%28abc%29%5E2%7D%7D&bg=e6e6e6&fg=333333&s=0&c=20201002)
2)(Nguyễn Huỳnh Khôi Nguyên&Đào Duy Hoàng)
Cho a,b,c>0 thỏa 
![\sqrt[4]{a^3+\frac{4}{3}} +\sqrt[4]{b^3+\frac{4}{3}}+ \sqrt[4]{c^3+\frac{4}{3}} \geq \sqrt[4]{(a+b+c)^3+27(\sum{a^2b}+\sum{ab^2})}](https://s0.wp.com/latex.php?latex=%5Csqrt%5B4%5D%7Ba%5E3%2B%5Cfrac%7B4%7D%7B3%7D%7D+%2B%5Csqrt%5B4%5D%7Bb%5E3%2B%5Cfrac%7B4%7D%7B3%7D%7D%2B+%5Csqrt%5B4%5D%7Bc%5E3%2B%5Cfrac%7B4%7D%7B3%7D%7D+%5Cgeq+%5Csqrt%5B4%5D%7B%28a%2Bb%2Bc%29%5E3%2B27%28%5Csum%7Ba%5E2b%7D%2B%5Csum%7Bab%5E2%7D%29%7D&bg=e6e6e6&fg=333333&s=0&c=20201002)
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Anh Nguyên solve thử cái này xem!:D
http://mathfriend.org/forum/index.php?showtopic=13756
Hè!
khoi nguyen chi tui thiet ke web mau
sao tui thiet ke web tui de qua